1. a = 8.
b = 15
c = 17.
c^2 = 17^2 = 289.
a^2 + b^2 = 64 + 225 = 289 = c^2.
Answer: Yes.
2. Z = 7 = hyp.
X = 7*cos30 = 6.06 = hor. side.
Y = 7*sin30 = 3.5 = ver. side.
P = 7 + 6.06 + 3.5 = 16.56.
3. We form a rt triangle:
X = -18 Miles = Hor. side.
Y = -5 Miles = Ver. side.
Z = Hyp.
tanAr = Y/X = -5 / -18 = 0.27777.
Ar = 15.5 Deg. = Reference angle.
A = 180 + 15.5 = 195.5 Deg., CCW.
Z = X/cosA = -18 / cos195.5=18.7 Miles
= Magnitude.
Direction = 195.5 Deg. CCW = 15.5 Deg.
South of west.
PLEASE HELP WITH A FEW QUESTIONS
triangle ABC has side lengths 8, 15, and 17 do the side lengths form a pythagorean triple?
the length of the hypotenuse of a 30-60-90 triangle is 7 find perimeter
to approach the runway, a pilot of a small plane must begin a 10descent starting from a height of 1,790 feet above the ground to the nearest tenth of a mile how many miles from the runaway is the airplane at the start of this approach
my answer 0.3mi
a glider lands 18miles west and 5 miles south from where it took off the result of the trip can be described by the vector(-18,-5)use distance(magnitude)and direction to describe this vector a second way.
i know it's south of west but not sure of the miles
6 answers
stoopid
Its crazy how this was question 10 years ago these dudes are probably fathers now
ikr
what is the answer to this question?
Sorry, which question are you referring to? Please provide more information.