Asked by James
7. Two cars are moving. The first car has twice the mass of the second car, but only half as much kinetic energy. Then, both cars increase their speed by 8.00 m/s. They then have the same kinetic energy. The original speeds of the two cars are, respectively,
A. v1 = 5.66 m/s, v2 = 11.3 m/s.
B. v1 = 14.1 m/s, v2 = 7.07 m/s.
C. v1 = 11.3 m/s, v2 = 5.66 m/s.
D. v1 = 22.6 m/s, v2 = 11.3 m/s.
E. v1 = 14.1 m/s, v2 = 22.6 m/s.
A. v1 = 5.66 m/s, v2 = 11.3 m/s.
B. v1 = 14.1 m/s, v2 = 7.07 m/s.
C. v1 = 11.3 m/s, v2 = 5.66 m/s.
D. v1 = 22.6 m/s, v2 = 11.3 m/s.
E. v1 = 14.1 m/s, v2 = 22.6 m/s.
Answers
Answered by
Elena
À. v1 = 5.66 m/s, v2 = 11.3 m/s.
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