Asked by Carolyn
Minnie and Steve have arectangular swimming pool that is 12 ft. wide and 20 feet long. They are going to build a tile border of uniform width around the pool. They have 160 sq. ft. of tile. How wide should the border be?
Answers
Answered by
Reiny
area of pool only = 12x20 = 240 ft^2
let the width of the border be x ft
so area of pool + border
= (12+2x)(20+2x) = 4x^2 + 64x + 240
New area - pool area = tile area
4x^2 + 64x + 240 - 240 = 160
4x^2 + 64x - 160 = 0
x^2 + 16x - 40 = 0
complete the square
x^2 + 16x + 64 = 40 + 64
(x+8)^2 = 104
x+8 = √104
x = ±√104 - 8
x = appr 2.2 ft or a negative, which would be silly
the border should be 2.2 ft wide
(good luck finding a 2.2 ft tile, looks like a lot of wasteful cutting)
let the width of the border be x ft
so area of pool + border
= (12+2x)(20+2x) = 4x^2 + 64x + 240
New area - pool area = tile area
4x^2 + 64x + 240 - 240 = 160
4x^2 + 64x - 160 = 0
x^2 + 16x - 40 = 0
complete the square
x^2 + 16x + 64 = 40 + 64
(x+8)^2 = 104
x+8 = √104
x = ±√104 - 8
x = appr 2.2 ft or a negative, which would be silly
the border should be 2.2 ft wide
(good luck finding a 2.2 ft tile, looks like a lot of wasteful cutting)
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.