Asked by kim
600(x^2+x+1) using the formula -b+/- sqrtb^-4ac/2a
Answers
Answered by
Reiny
are you solving
600(x^2 + x + 1) = 0 ?
I will assume that, or else you have noting to solve.
divide each side by 600
x^2 + x + 1 = 0
x = (-1 ± √-3)/2
or (-1 ± i√3)/2 , a pair of complex numbers.
600(x^2 + x + 1) = 0 ?
I will assume that, or else you have noting to solve.
divide each side by 600
x^2 + x + 1 = 0
x = (-1 ± √-3)/2
or (-1 ± i√3)/2 , a pair of complex numbers.
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