Asked by Ant14
The sum of the ages of Travis, Mac and Ellie is 44. Travis is 4 years older than Ellie and Mac is twice as old as Ellie. How old is each?
Answers
Answered by
Jai
let x = age of Travis
let x-4 = age of Ellie (since Travis is four years older than Ellie)
let 2(x-4) = age of Mac (since he is twice older than Ellie)
since the sum of their ages is 44,
x + x - 4 + 2(x - 4) = 44
2x - 4 + 2x - 8 = 44
4x - 12 = 44
4x = 56
x = 14 yrs old (Travis)
x-4 = 10 yrs old (Ellie)
2(x-4) = 20 yrs old (Mac)
hope this helps~ :)
let x-4 = age of Ellie (since Travis is four years older than Ellie)
let 2(x-4) = age of Mac (since he is twice older than Ellie)
since the sum of their ages is 44,
x + x - 4 + 2(x - 4) = 44
2x - 4 + 2x - 8 = 44
4x - 12 = 44
4x = 56
x = 14 yrs old (Travis)
x-4 = 10 yrs old (Ellie)
2(x-4) = 20 yrs old (Mac)
hope this helps~ :)
Answered by
CHIMA
A CIRCULAR PIECE OF CARDBOARD IS TRIMMEM IN SUCH A WAY THAT ITS CIRCUMFERENCE IS REDUCED IN THE RATIO 3:7. IN WHAT RATIO IS THE SURFACE AREA REDUCED?
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