Question
two motorcyclists started at the same point and travel in opposite directions. one travels 6 mph faster than the other.In 4 hours they are 432miles apart. how fast is each traveling?
speed of slower mph
speed of faster mph
speed of slower mph
speed of faster mph
Answers
let speed of slower be x mph
then speed of the faster is x+6 mph
distance covered by slower = 4x
distance covered by faster = 4(x+6)
4x + 4(x+6) = 432
8x + 24=432
8x = 408
x = 51
the slower went 51 mph, the faster went 57 mph
then speed of the faster is x+6 mph
distance covered by slower = 4x
distance covered by faster = 4(x+6)
4x + 4(x+6) = 432
8x + 24=432
8x = 408
x = 51
the slower went 51 mph, the faster went 57 mph
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