Asked by Abhishek
If y=e^x+3logx then prove that dy/dx=x^2(x+3)e^x.
Answers
Answered by
Bosnian
d ( e ^ x ) / dx = e ^ x
d ( log x ) / dx = 1 / x
d y / dx = e ^ x + 3 * 1 / x
d y / dx = e ^ x + 3 / x
d ( log x ) / dx = 1 / x
d y / dx = e ^ x + 3 * 1 / x
d y / dx = e ^ x + 3 / x
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