Asked by nena ochoa
                2)If the scale factor of a map is 1/8” is 12 miles.  How far apart are two towns if they are 3 inches apart on the map? 
help with graphing?
1)Graph the function y = 2x2 – 3. You can describe your graph by specifying the vertex, maximum or minimum, axis of symmetry, and 4 points on the parabola, two on each side of the axis of symmetry.
2)You have 32 feet of fencing to enclose a garden. The function A=16x-x2, where x=width, gives you the area of the garden in square feet.
 
a.What is the maximum area?
b.What width gives you the maximum area?
4) Solve x2 -8x +15 =0 by factoring.
            
        help with graphing?
1)Graph the function y = 2x2 – 3. You can describe your graph by specifying the vertex, maximum or minimum, axis of symmetry, and 4 points on the parabola, two on each side of the axis of symmetry.
2)You have 32 feet of fencing to enclose a garden. The function A=16x-x2, where x=width, gives you the area of the garden in square feet.
a.What is the maximum area?
b.What width gives you the maximum area?
4) Solve x2 -8x +15 =0 by factoring.
Answers
                    Answered by
            Damon
            
    1/8 = .125
so
.125/12 = 3/x
x = 36/.125 = 288 miles
    
so
.125/12 = 3/x
x = 36/.125 = 288 miles
                    Answered by
            Damon
            
    1)Graph the function y = 2x2 – 3. You can describe your graph by specifying the vertex, maximum or minimum, axis of symmetry, and 4 points on the parabola, two on each side of the axis of symmetry.
2 x^2 - 3 = y complete the square
x^2 - 1.5 = .5 y
x^2 = .5 y + 1.5
(x-0)(x-0) = .5 (y + 3)
vertex at (0,-3)
axis of symmetry at x = 0
minimum at vertex
You can do points, x = +/-1 and x = +/- 2
    
2 x^2 - 3 = y complete the square
x^2 - 1.5 = .5 y
x^2 = .5 y + 1.5
(x-0)(x-0) = .5 (y + 3)
vertex at (0,-3)
axis of symmetry at x = 0
minimum at vertex
You can do points, x = +/-1 and x = +/- 2
                    Answered by
            Damon
            
    2)You have 32 feet of fencing to enclose a garden. The function A=16x-x2, where x=width, gives you the area of the garden in square feet.
a.What is the maximum area?
b.What width gives you the maximum area?
===========
perimeter = 2x+2y= 32
or y = (16-x)
A = x (16-x) = 16 x - x^2 sure enough
now same deal, complete the square to find vertex
x^2 - 16 x = -A
x^2 - 16 x + 64 = -A + 64
(x-8)^2 = - (A-64)
vertex at A = 64 and x = 8
                    Answered by
            Damon
            
    4) Solve x2 -8x +15 =0 by factoring.
Hey, did you try ???
(x-5)(x-3) = 0
x = 5 or x = 3
    
Hey, did you try ???
(x-5)(x-3) = 0
x = 5 or x = 3
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