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A compact disc spins at 2.3 revolutions per second. An ant is walking on the CD and finds that it just begins to slide off the...Question
A compact disc spins at 2.8 revolutions per second. An ant is walking on the CD and finds that it just begins to slide off the CD when it reaches a point 3.2 cm from the CD's center.
What is the coefficient of friction between the ant and the CD?
What is the coefficient of friction between the ant and the CD?
Answers
Damon
2.8 * 2 pi radians/s = 17.6 rad/s
r = .032 meters
Ac = w^2 r = (17.6)^2(.032) = 9.9 m/s^2
m g (mu) = m Ac
mu g = 9.9
mu (9.8) = 9.9
mu is about 1
r = .032 meters
Ac = w^2 r = (17.6)^2(.032) = 9.9 m/s^2
m g (mu) = m Ac
mu g = 9.9
mu (9.8) = 9.9
mu is about 1
Alex
Thank you so much!