P = XH2O*Po
So you need to calculate mols NaOH and mols H2O, then XH2O and substitute into the above with Po = 760.
Pvap (mm-Hg) of 100g 24%NaOH in H2O @100C? When Pvap pure H2O @100C is 760mm-Hg
Pls where to start solving this problem? What is the equation? What are the staeps to get to the right answer?
2 answers
Thx! for Mole of H2O: I took 76g since it is 100g of 24%NaOH solution ????
Then,
Mole of H2O: 76/18=4.222
Mole of NaOH: 24/39.997=0.6
Total moles: 4.222+0.6=4.822
X1=4.222/4.822=0.876
P1=0.876x760=665.76 mm Hg
Then,
Mole of H2O: 76/18=4.222
Mole of NaOH: 24/39.997=0.6
Total moles: 4.222+0.6=4.822
X1=4.222/4.822=0.876
P1=0.876x760=665.76 mm Hg
1 answer