Asked by marina
Pvap (mm-Hg) of 100g 24%NaOH in H2O @100C? When Pvap pure H2O @100C is 760mm-Hg
Pls where to start solving this problem? What is the equation? What are the staeps to get to the right answer?
Pls where to start solving this problem? What is the equation? What are the staeps to get to the right answer?
Answers
Answered by
DrBob222
P = XH2O*P<sup>o</sup>
So you need to calculate mols NaOH and mols H2O, then XH2O and substitute into the above with P<sup>o</sup> = 760.
So you need to calculate mols NaOH and mols H2O, then XH2O and substitute into the above with P<sup>o</sup> = 760.
Answered by
marina
Thx! for Mole of H2O: I took 76g since it is 100g of 24%NaOH solution ????
Then,
Mole of H2O: 76/18=4.222
Mole of NaOH: 24/39.997=0.6
Total moles: 4.222+0.6=4.822
X1=4.222/4.822=0.876
P1=0.876x760=665.76 mm Hg
Then,
Mole of H2O: 76/18=4.222
Mole of NaOH: 24/39.997=0.6
Total moles: 4.222+0.6=4.822
X1=4.222/4.822=0.876
P1=0.876x760=665.76 mm Hg
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