C(5,3) = (5*4*3)/(1*2*3) = 20
There are 5*4*3 ways to arrange the students, but if the order doesn't matter, all 3! orderings involve the same people.
Ralph, Mario, Jack, Laura, and Maria are in the math club. The club advisor will assign students to 3-person teams at the next math team competition. How many different 3-person teams can be formed from these five students?
I got this wrong...here was my answer
5*4*3/(2*1) 60/2 30 teams combination
3 answers
Thank you!!!!
Uh... (5*4*3)/(1*2*3) = 10
...doesn't it? Google and my calculator say so xD
...doesn't it? Google and my calculator say so xD