Asked by Martin
Given that the mass of an electron is 9.1 x 10^-28 grams and the charge on an electron is 1.6 x 10^-19 Coulombs, calculate the voltage required to lift an electron 5 cm.
not quite sure how to do this.
not quite sure how to do this.
Answers
Answered by
Damon
Potential energy gain = q V = m g h
V = m g h/q
V = 9.1 * 10^-28*10^-3 * 9.8 *5*10^-2 / 1.6*10^-19
V = m g h/q
V = 9.1 * 10^-28*10^-3 * 9.8 *5*10^-2 / 1.6*10^-19
Answered by
Martin
Hi Damon .. where did the 10^-3 come from? .. I understand the 9.8 is gravity and the 5 is 5 cm
Answered by
drwls
Damon used kg for mass and meters for distance. Those units go with the 9.8 m/s^2 for g. The 10^-3 and 10^-2 are conversion factors from grams and cm.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.