a. label the forces at the supports, and the hanging end.
Here it is in my head:
the angle at the rope to horizontal is Theta. W is the weight of the sign. T is tension.
Torque about A:
Tension*Lengthstring*cosTheta-Weight=0
but cosTheta= .48/lengthstring
A circular shop sign of mass 10kg is to be hung from the wall of the shop.
The sign hangs from a light, rigid horizontal support of length 0.48m that is hinged to the wall at one end A. The other end B of the support is attached by a model string to a point C at a distance 0.2m vertically above the point A. You may model the sign as a particle located below the midpoint of the horizontal support AB.
By taking torques abut the hinged end A, and considering equilibrium of the beam, find the tension in the rope.
1 answer
1 answer