Asked by jenika

y=2x-1
2x-y-1=0

a)this sytem has excatly onw solution
b)this system has indinetly many solutions
c)this system has no solution
d)(1,1) and (0,0)
Answered by Reiny
mmmmhhh?
Isn't the second equation the same as the first?

And how many points would satisfy the first?

So what do you think?
Answered by jenika
ohhhh so just one solution right?
Answered by Rezu
If you mean infinite not indinetly than the answer is C.
2x-y-1=0 subtract 2x from each side
-y-1 = -2x + 0 add 1 to each side
-y = -2x + 1 multiply everything by -1
y = 2x-1
The equations are equal, so the system has infinite solutions.
Answered by jenika
oh ok thanks alot
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