73 7/10−25 5/8

1 answer

To perform the subtraction \(73 \frac{7}{10} - 25 \frac{5}{8}\), we first convert the mixed numbers into improper fractions.

  1. Convert \(73 \frac{7}{10}\) to an improper fraction:

\[ 73 \frac{7}{10} = \frac{73 \times 10 + 7}{10} = \frac{730 + 7}{10} = \frac{737}{10} \]

  1. Convert \(25 \frac{5}{8}\) to an improper fraction:

\[ 25 \frac{5}{8} = \frac{25 \times 8 + 5}{8} = \frac{200 + 5}{8} = \frac{205}{8} \]

  1. Now we need to perform the subtraction:

\[ \frac{737}{10} - \frac{205}{8} \]

  1. Find a common denominator. The least common multiple (LCM) of 10 and 8 is 40. Convert both fractions:

\[ \frac{737}{10} = \frac{737 \times 4}{10 \times 4} = \frac{2948}{40} \]

\[ \frac{205}{8} = \frac{205 \times 5}{8 \times 5} = \frac{1025}{40} \]

  1. Subtract the fractions:

\[ \frac{2948}{40} - \frac{1025}{40} = \frac{2948 - 1025}{40} = \frac{1923}{40} \]

  1. Simplify \(\frac{1923}{40}\) if possible. Since 1923 and 40 have no common factors other than 1, the improper fraction can't be simplified further.

  2. Convert back to a mixed number:

To convert \(\frac{1923}{40}\) to a mixed number:

  • Divide 1923 by 40.

Calculating \(1923 \div 40 = 48\) remainder \(3\).

Thus, we can write:

\[ \frac{1923}{40} = 48 \frac{3}{40} \]

To summarize: \[ 73 \frac{7}{10} - 25 \frac{5}{8} = 48 \frac{3}{40} \]