Asked by Jasmine
Given the following thermochemical data:
1) C(s) + O2(g) -> CO2(g) ∆H = -393.5 kJ
2) H2(g) + 1/2 O2(g) -> H2O(l) ∆H = -285.8 kJ
3) 3 C(s) + 3 H2(g) -> C3H6(g) ∆H = +20.4 kJ
4) C3H6 (cyclopropane)(g) -> C3H6(propene)(g) ∆H = -33.0 kJ
What is the ∆H for the following reaction?
C3H6 (cyclopropane)(g) + 9/2 O2(g) -> 3CO2(g)∆H = ______.
1) C(s) + O2(g) -> CO2(g) ∆H = -393.5 kJ
2) H2(g) + 1/2 O2(g) -> H2O(l) ∆H = -285.8 kJ
3) 3 C(s) + 3 H2(g) -> C3H6(g) ∆H = +20.4 kJ
4) C3H6 (cyclopropane)(g) -> C3H6(propene)(g) ∆H = -33.0 kJ
What is the ∆H for the following reaction?
C3H6 (cyclopropane)(g) + 9/2 O2(g) -> 3CO2(g)∆H = ______.
Answers
Answered by
DrBob222
Your target equation is not balanced.
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