the electric field of q1 E1
the electric field of q2 E2
Net electric field is vector sum of
electric fields due to q1 and q2.
the point to the left from origin:
E1←,→ E2 (can give zero)
the point between q1 and q2 :
E1 →,→ E2.(can’t give zero)
the point to the right from q2:
E1→,← E2. (E2>E1, =>can’t give zero).
Let's find the location of the point where electric field is zero.
k•q1•q3/r1² = k•q2•q3/r2²,
r1 =x,
r2 = x+d, where d = 0.4 m.
2/x² = 4/(x+d)²,
x² - 2•d•x - d² = 0.
Solve for x.
x1 = 0.954 m (to the left from origin - both for positive and negative q3)
x2 = - 0.164 m (is unsuitable)
Consider a charge of +2.0 C placed at the origin of an X-Y co-ordinate system and a charge of -4.0 C placed 40.0 cm to the right. Where must a third charge be placed – between the charges, to the left of the origin, or beyond the second charge – to experience a net force of zero? Argue your case qualitatively without working out a solution. Consider both positive and negative charges.
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1 answer