Asked by Anonymous
Ok i understand how to do these I'm just stuck on this one:
secx + tanx = 1
secx + tanx = 1
Answers
Answered by
Steve
1/cos + sin/cos = 1
1 + sin = cos
1 + 2sin + sin^2 = cos^2 = 1 - sin^2
2sin^2 + 2sin = 0
2sin(sin+1) = 0
sin=0 or sin = -1
x = 0, π, 3π/2
but, sec and tan are not defined at 3π/2, and π does not satisfy the original equation, so the solution is 0.
so, x = 2nπ for any integer n.
1 + sin = cos
1 + 2sin + sin^2 = cos^2 = 1 - sin^2
2sin^2 + 2sin = 0
2sin(sin+1) = 0
sin=0 or sin = -1
x = 0, π, 3π/2
but, sec and tan are not defined at 3π/2, and π does not satisfy the original equation, so the solution is 0.
so, x = 2nπ for any integer n.