0.80 mol/L of A and B are mixed. They react very slowly to produce C and D as follows:

A(aq) + B(aq) ⇔ C(aq) + 2D(aq)
When equilibrium is attained, the concentration of C is 0.60 mol/L and the concentration of A is:
a) 0.20 M
b) 0.40 M
c) 0.60 M
d) 0.80 M

1 answer

Isn't this just subtraction of one reagent from another?
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