Asked by Anonymous
A field is in the form of a triangle pictured below. Angle A is 85± and angle B is 78±. The distance between B and C is 269 feet. Find, to the nearest foot, the distance between A and B.
Answers
Answered by
Steve
angle C is 180-85-78 = 17
c/sinC = a/sinA
c/sin17 = 269/sin85
c=79
c/sinC = a/sinA
c/sin17 = 269/sin85
c=79
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