Asked by Anonymous
Please Help!!
Using heat of fusion, Specific heat, or heat of evaporation.
Calories to condense 135g of steam at 100 degrees C and to cool the liquid to 15 degrees C.
This is how I calculated it using heat of evaporation:
135gx540 cal=72900cal
72900cal/135g x (delta T)85 degrees C= 6.4
I know the correct answer is 8.44 x 10^4
So what did I do wrong?
Thank you!
Using heat of fusion, Specific heat, or heat of evaporation.
Calories to condense 135g of steam at 100 degrees C and to cool the liquid to 15 degrees C.
This is how I calculated it using heat of evaporation:
135gx540 cal=72900cal
72900cal/135g x (delta T)85 degrees C= 6.4
I know the correct answer is 8.44 x 10^4
So what did I do wrong?
Thank you!
Answers
Answered by
DrBob222
35gx540 cal=72900cal
<b>This first step is right. 72.9 kcal to condense 135 g steam at 100 C to liquid at 100 C. The error is the next step.
The next step is heat removed to cool liquid water at 100 to 15 C is
135g x 1 cal/g*C x (15-100) = ?
Then add step 1 to step 2 for total heat released.
72900cal/135g x (delta T)85 degrees C= 6.4
I know the correct answer is 8.44 x 10^4 </b>
<b>This first step is right. 72.9 kcal to condense 135 g steam at 100 C to liquid at 100 C. The error is the next step.
The next step is heat removed to cool liquid water at 100 to 15 C is
135g x 1 cal/g*C x (15-100) = ?
Then add step 1 to step 2 for total heat released.
72900cal/135g x (delta T)85 degrees C= 6.4
I know the correct answer is 8.44 x 10^4 </b>
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