Asked by Anonymous
if givin 115 osculations in 2.40 seconds, what is the length of the pendulum
Answers
Answered by
drwls
The frequency is
f = 115/2.4 = 47.92 Hz
f = [1/(2*pi)]*sqrt(g/L)
Solve for L, the length.
f = 115/2.4 = 47.92 Hz
f = [1/(2*pi)]*sqrt(g/L)
Solve for L, the length.
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