I =q/t = 47•10^-3/19 =2.47•10^-3 A .
Q =I•t1 = 2.47•10^-3 • 60 = 0.148 C.
N =Q/e = 0.148/1.6•10^-19= 9.3•10^17
A net charge of 47 mC passes through the cross-sectional area of a wire in 19.0 s.
(a) What is the current in the wire?
1 A
(b) How many electrons pass the cross-sectional area in 1.0 min?
2 electrons
2 answers
both of these are wrong?
2 answers