Asked by Andrea

Calculate the volume of Ba(OH)2 0.20 M necessary to neutralize 300.0 mL of H3PO4 0.30 M. (4 marks)
Answered by DrBob222
3Ba(OH)2 + 2H3PO4 ==> Ba3(PO4)2 + 6H2O

mols H3PO4 = M x L = ?
Use the coefficients to convert from mols H3PO4 to mols Ba(OH)2. Then, M Ba(OH)2 = mols Ba(OH)2/L Ba(OH)2
Answered by Nathan
how
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