Volumes of pyramids above the cutting planes are proportional to the cube of the height.
So the volume above the cutting plane at h/4 is
V1=(3/4)^3*100=2700/64 in³
Volume above the 2h/3 cut is
V2=(1/3)^3*100=100/27 in³
The volume between two cuts are therefore
= V1-V2
=100(27/64-1/27)
=16625/432
=38.48 in³ (approx.)
2 planes parallel to the base of a pyramid cut the pyramid at 1/4 and 2/3 of the height as measured from the base up. If the volume of the pyramid is 100 cubic inches, what is the volume of the middle piece to the nearest tenth?
3 answers
Thank you very much!
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