Asked by John
CaC2 (s) + 2 H20 (g) -> Ca(OH)2 (s) + C2H2 (g)
The complete reaction of 22.7 g of CaC2 requires consumption of ________g of H2O.
I did 22.7 g CaC2* (2/64 mols CaC2) = .709
Right?!?!
The complete reaction of 22.7 g of CaC2 requires consumption of ________g of H2O.
I did 22.7 g CaC2* (2/64 mols CaC2) = .709
Right?!?!
Answers
Answered by
DrBob222
You are correct that the reaction consumed 0.709 mols H2O; however, the problem asked for grams.
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