Asked by Bob
A 1200-kg frictionless roller coaster starts from rest at a height of 24 m. What is its kinetic energy when it goes over a spot that is 12 m high?
Answers
Answered by
Henry
PE=€mgh=1200 * 9.8 * 24=282,240 Joules.
KE = 0.
PE + KE = 282,340 J.
PE = 1200 * 9.8 * 12=141,120 J. @ 12 m.
141,120 + KE = 282,240
KE = 282,240 - 141,120 = 141,120 J.
KE = 0.
PE + KE = 282,340 J.
PE = 1200 * 9.8 * 12=141,120 J. @ 12 m.
141,120 + KE = 282,240
KE = 282,240 - 141,120 = 141,120 J.