Asked by Jessica
The probability that a team will carry the puck over the opposing team's blue line is 0.6, the probability that they get a shot on the net is 0.3, the probability that they get a shot away and score is 0.01 and the probability that they cross the blue line and score is 0.005. find the probability that they score given that
a) they cross the blue line
b) they get a shot away
a) they cross the blue line
b) they get a shot away
Answers
Answered by
MathMate
Use conditional probability
P(A|B)=P(A∩B)/P(B)
P(B)=blue line = 0.6
P(N)=shot on net=0.3
P(N∩S)=on net & score = 0.01
P(B∩S)=blue line & score = 0.005
P(B∩S|B)
=P(B∩S)/P(B)
=0.005/0.6=0.0833
P(N∩S|N)
=P(N∩S)/P(N)
=0.01/0.3=0.0333
P(A|B)=P(A∩B)/P(B)
P(B)=blue line = 0.6
P(N)=shot on net=0.3
P(N∩S)=on net & score = 0.01
P(B∩S)=blue line & score = 0.005
P(B∩S|B)
=P(B∩S)/P(B)
=0.005/0.6=0.0833
P(N∩S|N)
=P(N∩S)/P(N)
=0.01/0.3=0.0333
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