Asked by ted
How do you find the number of zeros in this equation:
f(x)=3x^2-5
please help
f(x)=3x^2-5
please help
Answers
Answered by
Bosnian
3 x ^ 2 - 5 = 0 Add 5 to both sides
3 x ^ 2 - 5 + 5 = 0 + 5
3 x ^ 2 = 5 Divide both sides by 3
x ^ 2 = 5 / 3
x = + OR - sqrt ( 5 / 3 )
2 solutions :
x = sqrt ( 5 / 3 )
and
- sqrt ( 5 / 3 )
3 x ^ 2 - 5 + 5 = 0 + 5
3 x ^ 2 = 5 Divide both sides by 3
x ^ 2 = 5 / 3
x = + OR - sqrt ( 5 / 3 )
2 solutions :
x = sqrt ( 5 / 3 )
and
- sqrt ( 5 / 3 )
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