How do you find the number of zeros in this equation:

f(x)=3x^2-5
please help

1 answer

3 x ^ 2 - 5 = 0 Add 5 to both sides

3 x ^ 2 - 5 + 5 = 0 + 5

3 x ^ 2 = 5 Divide both sides by 3

x ^ 2 = 5 / 3

x = + OR - sqrt ( 5 / 3 )

2 solutions :

x = sqrt ( 5 / 3 )

and

- sqrt ( 5 / 3 )
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