Asked by Cj
Jeff wants to start a lawn maintenance service to earn money for college. He wants to charge $25 for a small lawn and $35 for a large one. It takes him an average of 2 hours to mow and trim a small lawn and 3 hours to do a large one. He wants to make at least $250 a week but can work no more than 20 hours every week.
If x is the number of small lawns and y is the number of large lawns, which ordered pair is a solution to the system of inequalities which describes Jeff's situation?
If x is the number of small lawns and y is the number of large lawns, which ordered pair is a solution to the system of inequalities which describes Jeff's situation?
Answers
Answered by
Steve
Don't see any choices, but we do know
2x + 3y <= 20
25x + 35y >= 250
If he does 10 small lawns, that's 20 hrs and $250
He can't do any large lawns, since he can do at most 8 small lawns for $200, and can't make up the difference and stay under 20 hours:
S L Hrs $$$
10 0 20 250
9 0 18 225
8 1 19 235
7 2 20 245
6 2 18 220
. . .
2x + 3y <= 20
25x + 35y >= 250
If he does 10 small lawns, that's 20 hrs and $250
He can't do any large lawns, since he can do at most 8 small lawns for $200, and can't make up the difference and stay under 20 hours:
S L Hrs $$$
10 0 20 250
9 0 18 225
8 1 19 235
7 2 20 245
6 2 18 220
. . .
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.