Question
A child sitting 1.50m from the center of a merry-go-around moves with a speed of 1.10m/s .
Part a) Calculate the centripetal acceleration of the child.
Part b) Calculate the net horizontal force exerted on the child ( = 20.5 ).
Part a) Calculate the centripetal acceleration of the child.
Part b) Calculate the net horizontal force exerted on the child ( = 20.5 ).
Answers
Elena
m=20.5 kg ???
a=v²/R = (1.1)²/1.5 = 0.807 m/s²,
F=m•a = 20.5•0.807=16.5 N
a=v²/R = (1.1)²/1.5 = 0.807 m/s²,
F=m•a = 20.5•0.807=16.5 N