Asked by Sira
What would be the simplest way to eliminate one of the variables? Below is a system of three equations in three variables:
1. x+y+3z=7
2. 2x-4y+z=7
3. 3x+5y-4z=-6
1. x+y+3z=7
2. 2x-4y+z=7
3. 3x+5y-4z=-6
Answers
Answered by
Steve
one simple way is to substitute x #1 into #2 and #3:
2(7-y-3z) - 4y + z = 7
3(7-y-3z) + 5y - 4z = -6
which gives you
-6y -5z = -7
2y - 13z = -27
now we see 2y = 13z-27, so
-3(13z-27) - 5z = -7
-44z = -88
z = 2
so, y = (26-27)/2 = -1/2
and x = 7-(-1/2)-6 = 1/2
2(7-y-3z) - 4y + z = 7
3(7-y-3z) + 5y - 4z = -6
which gives you
-6y -5z = -7
2y - 13z = -27
now we see 2y = 13z-27, so
-3(13z-27) - 5z = -7
-44z = -88
z = 2
so, y = (26-27)/2 = -1/2
and x = 7-(-1/2)-6 = 1/2
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.