Asked by nichole

The mean of a set of normally distributed data is 550 and the standard deviation is 35.
What percent of the data is between 515 and 585?

Answers

Answered by MathMate
Normalize 515 and 585, namely
z(515)=(515-550)/35=-1
z(585)=(585-550)/35=1
The percent is the difference of probabilities of one-tail z-values between -1 and +1. It should be a little less than 70%.
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