f(day)=800*.45^(day)
Set f(day)=1, solve for day by taking a log on both sides.
In a financial deal, you are promised $800 the first day and each day after that you will receive 45% of the previous day's amount. When one day's amount drops below $1, you stop getting paid from that day on. What day is the first day you would receive no payment and what is your total income?
I am so confused about this problem. Could someone please show me the steps?
6 answers
instead of .45^(day) you should actually use .45^(day-1) so that the first day is 800
I tried doing this, but I still have no idea how to solve this problem =/
e.g.
day 1 = 800
day 2 = 800(.45)
day 3 = 800(.45)^2
looks like day (n+1) would be 800(.45)^n
..
when is 800(.45)^n = 1
.45^n = 1/800 = .00125
take log of both sides
log(.45^n) = log .00125
n log .45 = log .00125
n = log .00125/log .45 = 8.3
checking:
day 9 = 800(.45)^8 = 1.35
day 10 = 800(.45)^9 = .61 ----> receive no income
so he receives income for 9 days
so we want the sum of the geometric series of 9 terms
with a = 800 and r = .45
sum(9) = 800(1 - .45^9)/(1 - .45)
= 1453.44
day 1 = 800
day 2 = 800(.45)
day 3 = 800(.45)^2
looks like day (n+1) would be 800(.45)^n
..
when is 800(.45)^n = 1
.45^n = 1/800 = .00125
take log of both sides
log(.45^n) = log .00125
n log .45 = log .00125
n = log .00125/log .45 = 8.3
checking:
day 9 = 800(.45)^8 = 1.35
day 10 = 800(.45)^9 = .61 ----> receive no income
so he receives income for 9 days
so we want the sum of the geometric series of 9 terms
with a = 800 and r = .45
sum(9) = 800(1 - .45^9)/(1 - .45)
= 1453.44
I understand it now! Thank you so much!
i still don't get it
1 answer