Asked by CLUELESS
A proton that has a mass m and is moving at 250 m/s in the + direction undergoes a head-on elastic collision with a stationary oxygen nucleus of mass 16m. Find the velocities of the proton and the oxygen nucleus after the collision
i know i have to consider that both momentum and KE are conserved but i don't know what to do (how to do it)
i know i have to consider that both momentum and KE are conserved but i don't know what to do (how to do it)
Answers
Answered by
Elena
u1 = (m1-m2) •v/(m1+m2) – (m-16m) •250/(m+16m) = - 220.6 m/s,
Minus indicates that the proton is returned back due to the collision.
m1•v = m1•u1+m2•u2
u2 = (v+u1)m1/ m2 = 250 –(-220.6) •m/16•m = 29.4 m/s
in the direction of the initial direction of the proton.
Minus indicates that the proton is returned back due to the collision.
m1•v = m1•u1+m2•u2
u2 = (v+u1)m1/ m2 = 250 –(-220.6) •m/16•m = 29.4 m/s
in the direction of the initial direction of the proton.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.