Asked by sharmila

an architect wants to draw a rectangle with a diagonal of 13 inches.the length of the rectangle is to be 2 inches more thn twice the width.what dimensions should she make the triangle.

(a)set up an equation:

(b)solve the equation:

(c)write a sentence that answers the quation:
Answered by Henry
Dia. = 13 In. = Hyp. of rt triangle.
Width=x In.=Ver. side of a rt triangle
Length = 2x+2 In. = Hor. side of rt triangle.

a. (2x+2)^2 + x^2 = 13^2.

b. 4x^2+8x+4 + x^2 = 169
5x^2 + 8x -165 = 0
Use Quadratic Formula:
X = 5 In.
X = -6.6 Not valid.

2x+2 = 2*5 + 2 = 12 In.

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