Question
a father pulls hi children in a wagon for 25 minutes covering 1.25 miles on a level sidewalk. he pulls with an average force of 35 lbf at an angle of 45 degrees to the sidewalk.
(a) how much work is done (in ft.lbf)?
(b) what is the average horsepower required?
(a) how much work is done (in ft.lbf)?
(b) what is the average horsepower required?
Answers
bobpursley
work= force*distance*cosine45=
work= 35*.707*1.25*5280
horspower: work in ft-lbs/550
work= 35*.707*1.25*5280
horspower: work in ft-lbs/550