if the [H] of a solution at 25degrees is 1.7*10^-4 mol/L, calculate the [OH] in mol/L, the PH, and the pOH?

Answer 1

pH = -log(H^+)
pOH = -log(OH^-)
pH + pOH = pKw = 14 and
(H^+)(OH^-) = Kw.
One or more of the four above will calculate all you ever need to know abouat H^+), (OH^-), pH and pOH.

Answer 2

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