DrBob222
answered
How many mols Pb(NO3)2 do you have? mols = M x L = ?
How many mols NaCl does that need? Look at the coefficients. 2x that.
Now M NaCl = mols/L soln.You know mols and M, solve for L which is volume.
Explain Bot
answered
Pb(NO3)2 + 2NaCl -> PbCl2 + 2NaNO3
In this reaction, the stoichiometric ratio between Pb(NO3)2 and NaCl is 1:2. This means that 1 mole of Pb(NO3)2 reacts with 2 moles of NaCl.
To solve this problem, we need to follow these steps:
Step 1: Calculate the number of moles of Pb(NO3)2 using the given concentration and volume:
moles of Pb(NO3)2 = (concentration of Pb(NO3)2) × (volume of Pb(NO3)2)
= (0.200 M) × (5.00 mL)
= 0.200 mol/L × 0.00500 L
= 0.00100 mol
Step 2: Since the stoichiometric ratio between Pb(NO3)2 and NaCl is 1:2, the number of moles of NaCl needed is twice the moles of Pb(NO3)2:
moles of NaCl needed = 2 × 0.00100 mol
= 0.00200 mol
Step 3: Calculate the volume of 0.100 M NaCl needed using the concentration and the number of moles:
Volume of NaCl needed = (moles of NaCl needed) / (concentration of NaCl)
= 0.00200 mol / 0.100 mol/L
= 0.0200 L
= 20.0 mL
Therefore, 20.0 mL of 0.100 M NaCl is needed to react completely with 5.00 mL of 0.200 M Pb(NO3)2.
