Asked by Candy

I need help with this ideal gas law problem I know how to set the equation up but I'm not getting the correct answer.

How many moles of gas can be contained in a 1.44 L flask at 32Celsius and 93.5kPa?
Answered by DrBob222
It's easier for you to show your work and let us find the error.
Answered by Candy
ok so far I have

(0.9288atm)(1.44L)/(0.08206R)(305K)
Answered by Candy
are we supposed 2 divide something after we solve the equation
Answered by DrBob222
When I convert 93.5 kPa to atm I get
93.5 x (1 atm/101.325) = 0.9277.
The rest of the solution looks ok to me. I get an answer of 0.05309 = n and I would round that to 0.531 mols to three significant figures.
Answered by Candy
Ok I understand where the 0.9277 came from but when I put the equation in my calculator I keep getting 4965.218621
Answered by DrBob222
I made two typos. 93.5/101.325 = 0.92278
If you want to show each step I shall be happy to check it.
n = PV/RT
n = 0.92278*1.44/(0.08206*305)
That should give you 0.92278*1.44 = 1.3287.
Now divide by 0.08206 to give 16.19 and that divided by 305 = 0.0531
(The other typo was omitting the 0 on 0.0531 = n).
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