Write the standard equation for the circle center (–6, –8), that passes through (0, 0). How would someone do this? I have been looking through all my notes from class and I don't understand how to do it.

Answer 1

very easy

You should be familiar with the standard form that shows the centre.
the equation would be
(x+6)^2 + (y+8)^2 = r^2
but (0,0) lies on it, so
6^2 + 8^2= r^2 = 100

(x+6)^2 + (y+8)^2 = 100

Answer 2

Thankyou very much :)