Substitute and solve for x then y.
x^2 + (2x+6)^2 = 8
x^2 + 4x^2 + 24x + 36 = 8
y=2x+6
x^2+y^2=8
10 answers
i have 5x^2+24x+28=0
PsyDAD what next?
PsyDAD what next?
X^2+24/5X+28/5=0
i got answer (-2,2) is this right?
too much work. Just use the quadratic formula.
Or, with a little work, you should be able to factor it:
(x+2)(5x+14) = 0
Then, knowing x, you can easily get y.
Or, with a little work, you should be able to factor it:
(x+2)(5x+14) = 0
Then, knowing x, you can easily get y.
(-2,2) is one solution.
and if I'm right is one more (-2.8,0.4)
is quadratic equation the first one semi-ellipse?
the two equations are a line and a circle.
mosey on over to wolframalpha . com and type in
plot y=2x+6, x^2+y^2=8, x=-5..5, y=-5..5
mosey on over to wolframalpha . com and type in
plot y=2x+6, x^2+y^2=8, x=-5..5, y=-5..5
thank you so much that really helped