Asked by david
Write an equation for a parabola with vertex at (3,- 6) and focus at (3,- 4).
Answers
Answered by
Henry
Given: V(3,-6), F(3,-4).
VF =1/4a = -4 -(-6).
1/4a = 2.
4a = 1/2.
a = 1/8.
Y = a(x-h)^2 + k.
Y = (1/8)(x-3)^2 -6.
VF =1/4a = -4 -(-6).
1/4a = 2.
4a = 1/2.
a = 1/8.
Y = a(x-h)^2 + k.
Y = (1/8)(x-3)^2 -6.
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