Asked by Liz
Calculate the pH of a 2.5x10-5 M lithium hydroxide solution.
Answers
Answered by
DrBob222
LiOH is a strong base; theefore, (OH^-) = (LiOH).
pOH = -log(OH^-), then
pH + pOH = pKw = 14
You know pOH and pKw, solve for pH.
pOH = -log(OH^-), then
pH + pOH = pKw = 14
You know pOH and pKw, solve for pH.
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