Asked by Derrick

Pure water is added to 25.0 mL of a 1.00 M HCL solution. The new solution has a volume of 2.00 L. What is the pH of the new solution.
Answered by DrBob222

1.00 M x (25.0 mL/2,000 mL) = (HCl)
pH = -log(HCl) = ?
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