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Asked by alya

find and sketch the natural domain of f(x,y)= √(x+y^2 )/(x^2+y^2 )
13 years ago

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Answered by Steve
well, the denominator is zero only at (0,0), so that is excluded

The numerator is real only when x > -y^2
13 years ago
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find and sketch the natural domain of f(x,y)= √(x+y^2 )/(x^2+y^2 )

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