Asked by Al
Jon and Remy were in a car race. When Jon finished the race in 45min, Remy had only driven 2/3 of the distance. Remy's average speed for the race was 50m/min less than Jon's.
a) Find the distance of the race.
b) What was Remy's speed?
a) Find the distance of the race.
b) What was Remy's speed?
Answers
Answered by
Henry
REMY
Speed = X m/min.
d = X * 45 m.
JON
Speed = (X-50) m/min.
2d/3 = (x-50)*45.
Multiply both sides by 3/2:
d = 67.5(X-50).
Substitute 45x for d:
45x = 67.5x - 3375.
45x - 67.5x = -3375.
-22.5x = - 3375.
b. X = -3375 / -22.5 = 150 m/min = 150m/60s = 2.5 m/s = Remy's speed.
a. d = 45x = 45min * 150m/min = 6750 m.
Speed = X m/min.
d = X * 45 m.
JON
Speed = (X-50) m/min.
2d/3 = (x-50)*45.
Multiply both sides by 3/2:
d = 67.5(X-50).
Substitute 45x for d:
45x = 67.5x - 3375.
45x - 67.5x = -3375.
-22.5x = - 3375.
b. X = -3375 / -22.5 = 150 m/min = 150m/60s = 2.5 m/s = Remy's speed.
a. d = 45x = 45min * 150m/min = 6750 m.
Answered by
Anonymous
Thank you.
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