Asked by Randy
calculate the molarity of an acetic acid solution if 39.96 mL of the solution is needed to neutralize 136mL of 1.41 M sodium hydroxide. the equation for the reaction is
HC2H3O2(aq) + NaOH(aq) > Na+(aq) + C2H3O2(aq)
+H2O(aq)
HC2H3O2(aq) + NaOH(aq) > Na+(aq) + C2H3O2(aq)
+H2O(aq)
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