Ask a New Question

Question

lim x--->pi/4 tanx - cotx / x - pi/4
13 years ago

Answers

bobpursley
I assume you have this:

LIM (tanx-cotx)/(x-PI/4) as x>>PI/4

which has a limit in the form of 0/0

L'Hopital's rule

= lim (sec^2x+csc^2x)/(-PI/4) which you can easily evaluate as x>>PI/4
13 years ago

Related Questions

( tanx/1-cotx )+ (cotx/1-tanx)= (1+secxcscx) Good one! Generally these are done by changing eve... tanx=cotx (tanx+cotx)over(tanx-cotx)=(1) over sin^2x-cos^2x) tanx-cotx/tanx+cotx=1-2cos squardx 1/tanx + 1/cotx =tanx +cotx verify prove that (cotx+tanx)(cotx-tanx) = 1/(sin^2 x) - 1/(cos^x) if tanx+cotx=2 then the value of tan^5x + cot^10x is ʃ ( tanx + cotx )² dx 1÷(tanx+cotx)(tanx+cotx)dx tanx cotx ------- + ------- = 1 +secxcscx 1 - cotx 1- tanx prove the proof
Ask a New Question
Archives Contact Us Privacy Policy Terms of Use