Asked by ZARNA
HOW DO YOU FACTOR A^3-27. PLEASE EXPLAIN IN DETAIL
Answers
Answered by
Reiny
it follows the difference of cubes pattern
A^3 - B^3 = (A-B)(A^2 + AB + b^2)
so (A-3)(.......)
tell me what you got.
A^3 - B^3 = (A-B)(A^2 + AB + b^2)
so (A-3)(.......)
tell me what you got.
Answered by
Guido
We have a difference of cubes.
Did you apply the formula given by Reiny?
If you did, there should be no more doubts.
A^3 - 27 = difference of cubes.
First, write 27 as an exponent.
What number when multiplied by itself 3 times will yield 27?
How about 3?
So, 3 x 3 x 3 = 27, right? This can be written 3^3.
We now have this:
A^3 - 3^3
Next, we apply the rule given to you by Reiny.
A^3 - B^3 = (A-B)(A^2 + AB + b^2)
Here, A = A and B = 3.
We plug and chug.
A^3 - 3^3 = (A - 3)(A^2 + 3A + 3^2)
A^3 - 3^3 = (A - 3)(A^2 + 3A + 9)
Done!
Did you apply the formula given by Reiny?
If you did, there should be no more doubts.
A^3 - 27 = difference of cubes.
First, write 27 as an exponent.
What number when multiplied by itself 3 times will yield 27?
How about 3?
So, 3 x 3 x 3 = 27, right? This can be written 3^3.
We now have this:
A^3 - 3^3
Next, we apply the rule given to you by Reiny.
A^3 - B^3 = (A-B)(A^2 + AB + b^2)
Here, A = A and B = 3.
We plug and chug.
A^3 - 3^3 = (A - 3)(A^2 + 3A + 3^2)
A^3 - 3^3 = (A - 3)(A^2 + 3A + 9)
Done!
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